If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X^2+13X+44=8
We move all terms to the left:
X^2+13X+44-(8)=0
We add all the numbers together, and all the variables
X^2+13X+36=0
a = 1; b = 13; c = +36;
Δ = b2-4ac
Δ = 132-4·1·36
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-5}{2*1}=\frac{-18}{2} =-9 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+5}{2*1}=\frac{-8}{2} =-4 $
| 24-x=19.5 | | 36=7w+2/2+w+5/4 | | y+42=4y | | 4(1+8x)=260 | | -20=4+4u | | 4c-9=5c+1 | | 9+y/44=5y/22 | | 8(2r-)-r=3(3r+2) | | X^+y^=113 | | 4(x-6)+6x=6x-8 | | 15x+31=-13 | | 9m=-3+10m | | 8+b•-4=5 | | x-12.5=50 | | -3-7v=88 | | -6n=7-5n | | (2x-9)-(x-3)=0 | | -(6x+7)+8=-19 | | 8t+10=10t | | 7m-8=56 | | 3(x+3=24 | | y=1/5–69/5+9 | | 1/12y+5=-16 | | -8b=-10−9b | | 15−4b=5 | | 5q-5=10q | | 3(x+2)/4-5(1-x)/6=1 | | 8x-(3x+10)=16 | | 13x+1=2x+13 | | x^2+4x-22.5=0 | | (3+2x)x=702 | | 8l=4 |